superquadratic

English

Etymology

From super- +‎ quadratic.

Pronunciation

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Adjective

superquadratic (not comparable)

1. (mathematics) Describing an extension of a quadratic function related to the superellipsoid
   • 2015, Wenmin Gong, Guangcun Lu, “Existence results for coupled Dirac systems via Rabinowitz-Floer theory”, in arXiv‎^[1]:

     In this paper, we construct the Rabinowitz-Floer homology for the coupled Dirac system \begin{equation*} \left\{ \begin{aligned} Du=\frac{\partial H}{\partial v}(x,u,v)\hspace{4mm} {\rm on} \hspace{2mm}M,\\ Dv=\frac{\partial H}{\partial u}(x,u,v)\hspace{4mm} {\rm on} \hspace{2mm}M, \end{aligned} \right. \end{equation*} where $M$ is an $n$-dimensional compact Riemannian spin manifold, $D$ is the Dirac operator on $M$, and $H:\Sigma M\oplus \Sigma M\to \mathbb {R}$ is a real valued superquadratic function of class $C^{1}$ with subcritical growth rates.